Friday, September 20, 2013

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1. P69 19 a. Max 3A+4B+0S1+0S2+0S3 s.t. -1A+2B+1S1=8 1A+2B+1S2=12 2A+1B+1S3=16 A, B, S1, S2, S3?0 b. When 2A+1B=16, 1A+2B=12 A=20/3=6.667 -1A+2B=8 1A+2B=12 2A+1B=16 -1A+2B=8 1A+2B=12 2A+1B=16 B=8/3=2.667 (6.667, 2.667) which is optimal solution Max 3A+4B= 3*6.667+4*2.667=30.667 c. -1A+2B+1S1=8 -6.667+2*2.667+S1=8 S1=9.333 1A+2B+1S2=12 6.667+2*2.667+S2=12 S2=0 2A+1B+1S3=16 2*6.667+1*2.667+S3=16 S3=0 2. P76 39 a.
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Let S= purchased units of the stock certificate memory M= purchased units of the money market fund R= guess MIN R=8S+3M 50S*10%+100M*4%?60,000 5S+4M?60,000 annual inc ome 50S+100M?1,200,000 investiture fund 100M?300,000 M?3,000 S?0 whenS=4,000, M=10,000 the net income become minimum $62,000 Objective stall (Min)| | | | | | carrell| lean| Original pry| Final nurse| | | | $B$15| Max be meshing| 62000| 62000| | | | | | | | | | | | | | | | | varying stalls| | | | | | electric cell| gens| Original evaluate| Final Value| integer| | | $B$12| Producted S| 4000| 4000| Contin| | | $C$12| Producted M| ten thousand| 10000| Contin| | | | | | | | | | | | | | | | Constraints| | | | | | Cell| observe| Cell Value| Formula| Status| Slack| | $B$19| Total Profit| 60000| $B$19>=$D$19| dorsum| 0| | $B$20| Total Profit| 1200000| $B$20<=$D$20| Binding| 0| | $B$21| Total Profit| 10000| $B$21>=$D$21| Not Binding| 7000| | $B$22| Total Profit| 0| $B$22<=$D$22| Binding| 0| b. 5S+4M=5*4000+4*10000=$60000 c. Max 5S+4M when S=18,000 M=3000, the annual impart pass on be maximum 102000 O bjective Cell (Max)| | | | | | Cell| Name|! Original Value| Final Value| | | | $B$15| Max Total Profit| 102000| 102000| | | | | | | | | | | | | | | | | Variable Cells| | | | | | Cell| Name| Original Value| Final Value| Integer| | | $B$12| Producted S|...If you want to get a full-of-the-moon essay, order it on our website: BestEssayCheap.com

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